英文字典中文字典


英文字典中文字典51ZiDian.com



中文字典辞典   英文字典 a   b   c   d   e   f   g   h   i   j   k   l   m   n   o   p   q   r   s   t   u   v   w   x   y   z       







请输入英文单字，中文词皆可：


请选择你想看的字典辞典：
单词字典翻译
trascendentalismo查看　trascendentalismo　在百度字典中的解释百度英翻中〔查看〕
trascendentalismo查看　trascendentalismo　在Google字典中的解释Google英翻中〔查看〕
trascendentalismo查看　trascendentalismo　在Yahoo字典中的解释Yahoo英翻中〔查看〕

安装中文字典英文字典查询工具!


中文字典英文字典工具:
选择颜色:
输入中英文单字

































































英文字典中文字典相关资料:


  • How do you use the important points to sketch the graph of y=x^2+6x+5 . . .
    The curve is above this vertex and is symmetrical about its axis #x=-3# This is parallel to y-axis Put y= o and solve #x^2+6x+5=0#
  • How do you solve the following system: 5x+y=-7, 6x - Socratic
    See a solution process below: Step 1) Solve the first equation for y: 5x + y = -7 -color(red)(5x) + 5x + y = -color(red)(5x) - 7 0 + y = -5x - 7 y = -5x - 7 Step 2
  • How do you use the important points to sketch the graph of y = x^2 − 6x . . .
    How do you use the important points to sketch the graph of y = x2 − 6x + 1? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs
  • Question #8e717 - Socratic
    See the proof below We need cos2x=cos^2x-sin^2x cos^2x+sin^2x=1 (a-b)^3=a^3-3a^2b+3ab^2-b^3 Therefore, LHS=cos^3 2x+3cosx = (cos^2x-sin^2x)^3+3 (cos^2x-sin^2x) =cos
  • Question #55a06 - Socratic
    -sqrt (9-6x-x^2)-3sin^-1 ( (x+3) (3sqrt2))+C Complete the square in the denominator: I=intx sqrt (- (x^2+6x)+9)dx=intx sqrt (- (x^2+6x+9)+9+9)dx I=intx sqrt (18- (x+
  • Question #91219 - Socratic
    Please see the process steps below; From how the question was understood, the interpretation is; We are looking for the unknown number, and let x be that number Statement! First Interpretation squareroot of 6 times the quantity of square root of 3 + 5 square root of 2 sqrt (6 xx x) color (white)x "of" color (white)x sqrt (3 + 5) color (white)x "of" color (white)x sqrt2 sqrt (6x) color
  • What is the factorization of #x^2+6x+9#? - Socratic
    The factored version is (x+3)^2 Here's how I approached it: I can see that x is in the first two terms of the quadratic, so when I factor it down it looks like: (x+a)(x+b) And when that gets expanded it looks like: x^2+(a+b)x+ab I then looked at the system of equations: a+b=6 ab=9 What caught my eye was that both 6 and 9 are multiples of 3 If you replace a or b with 3, you get the following
  • Question #47117 - Socratic
    1 Answer Rhys Dec 16, 2017 # e^ (-6x) = sum_ (n=0) ^oo ( (-6x)^n) (n!) or # e^ (-6x) = 1 -6x + 18x^2 - 36x^3 +
  • How do you solve #14= 6x - 93#? - Socratic
    See a solution process below: Step 1) Add color(red)(93) to each side of the equation to isolate the x term while keeping the equation balanced: 14 + color(red)(93) = 6x - 93 + color(red)(93) 107 = 6x - 0 107 = 6x Now, divide each side of the equation by color(red)(6) to solve for x while keeping the equation balanced: 107 color(red)(6) = (6x) color(red)(6) 107 6 = (color(red)(cancel(color
  • Question #bc25a - Socratic
    x=9 So we have: x-1=sqrt (6x+10) Let's try to remove the square root sign We square both sides (x-1)^2= (sqrt (6x+10))^2 x^2-2x+1=6x+10 We see that we can form a quadratic equation =>x^2-8x-9=0 Factor => (x+1) (x-9)=0 -1=x=9 Before we declare this as our final answer, we test each answer out into our original equation -1-1=sqrt (6*-1+10) =>-2=sqrt (4) =>-2!=2 This tells us that x=-1 is an





中文字典-英文字典  2005-2009