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  • How do you graph y=-x^2+4? | Socratic
    #-x^2 + 4 # is just #x^2# reflected in the x axis, then translated by # (0,4)# or in words, shifted upward by 4 units
  • How do you find the x and y intercepts for y= 3x-4? | Socratic
    x intercept: (4 3,0) y intercept: (0,-4) The x intercept is the point of the line for which y=0, so 0=3x-4 -> 3x=4 -> x=4 3 The y intercept is the point of the line for which x=0, so y=3*0-4 = -4
  • What is the vertex of #y= 2x^2 + 8x − 4#? - Socratic
    Explanation: we have #f (x)=2 (x^2+4x+4-4-4)=2 (x+2)^2-16# Answer link You can reuse this answer
  • How do you find the x and y intercept given y=4x+4 ? | Socratic
    to find the intercepts, that is where the graph crosses the x and y axes ∙ let x = 0, in the equation for y-intercept ∙ let y = 0, in the equation for x-intercept x = 0 → y = 0 +4 ⇒ y = 4 ← y-intercept y = 0 → 4x +4 = 0 ⇒ x = −1 ← x-intercept graph { (y-4x-4) ( (x+1)^2+ (y-0)^2-0 04) ( (x-0)^2+ (y-4)^2-0 04)=0 [-10, 10, -5, 5]}
  • How do you graph y=- x +4? | Socratic
    see explanation >This is the equation of a line When the line crosses the x-axis the y-coordinate will be zero Let y = 0 to find the x-intercept y = 0 : 0 = - x +4 → x = 4 → (4,0) is a point on the line Similarly , when the line crosses the y-axis , the x-coord will be zero Let x = 0 to find y-intercept x = 0 : y = 0 + 4 = 4 → ( 0,4) is a point on the line All that is required to
  • How do you solve using the completing the square method x^2 . . . - Socratic
    x=-0 76393202 or x=-5 23606797 color(red)(Commenci ng) color(red)(compl e ti ng) color(red)(the) color(red)(squ are) color(red)(method) color(red)(now,) 1) Know the formula for the perfect quadratic square, which is, (ax+-b)^2 = ax^2+-2abx+b^2 2) Figure out your a and b values, a= coefficient of x^2, which is 1 color(red)(b=6 (2(1)) = 3) 3) Move the 4 over to the right hand side, x^2+6x=-4 4
  • How do you find the x and y intercepts for y=1 2x-4? | Socratic
    Explanation: The y-intercept is the value of #y# when #x=0# Given #color (white) ("XXX")y=1 2x-4# when #x=0# #color (white) ("XXX")y=1 2 (0)-4=-4# The x-intercept is
  • What is the value of \frac { n ! } { ( n - r ) ! r ! when n=6 and r=4 . . .
    Hence the value of # (n!) ( (n-r)!r!)# (which is always a natural number), when #n=6# and #r=4# is
  • Complete the square to solve 4x2 + 24x = 4? - Socratic
    x=0 1623, -6 1623 nothing can be in the a spot to complete the square so divide everything by 4 x^2+6x=1 Divide b term by 2 then square it: (6 2)^2=9 add to both sides: x^2+6x+9=10 Now factor Tip the factor is ALWAYS going to be the b term divided by 2 in this case that is 3 (x+3)^2=10 Square root both sides to get x alone x+3=+-√10 x=-3+-√10 x=0 1623, -6 1623
  • How do you solve r^2-13r+36=0? | Socratic
    Factor the quadratic expression and then solve each term for 0 See full explanation below First, we need to factor the quadratic expression by playing with multipliers for 36 (1x36, 2x18, 3x12, 4x9, 6x6) which add to 13: (r - 9)(r - 4) = 0 Now we can solve each term for 0: Solution 1) r - 9 = 0 r - 9 + 9 = 0 + 9 r - 0 = 9 r = 9 Solution 1) r - 4 = 0 r - 4 + 4 = 0 + 4 r - 0 = 4 r = 4





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